Exercise 07-09:

##############################################################################
# Python From Scratch
# Author: Nilo Ney Coutinho Menezes
# Editora Novatec (c) 2010-2025 - LogiKraft 2025
# Site: https://pythonfromscratch.com
# ISBN: 978-85-7522-949-1 (Paperback), 978-85-7522-950-7 (hardcover), 978-85-7522-951-4 (ebook)
#
# File: chapter 07/exercise-07-09.py.py
##############################################################################
word = input("Enter the secret word:").lower().strip()
for x in range(100):
    print()
typed = []
hits = []
errors = 0
while True:
    password = ""
    for letter in word:
        password += letter if letter in hits else "."
    print(password)
    if password == word:
        print("You got it right!")
        break
    attempt = input("\nEnter a letter:").lower().strip()
    if attempt in typed:
        print("You already tried this letter!")
        continue
    else:
        typed += attempt
        if attempt in word:
            hits += attempt
        else:
            errors += 1
            print("You missed!")
    print("X==:==\nX  :   ")
    print("X  O   " if errors >= 1 else "X")
    line2 = ""
    if errors == 2:
        # The r before the string indicates that its content should not be processed
        # This way, we can use the characters \ and / without confusing them
        # with masks like \n and \t
        line2 = r"  |   "
    elif errors == 3:
        line2 = r" \|   "
    elif errors >= 4:
        line2 = r" \|/ "
    print(f"X{line2}")
    line3 = ""
    if errors == 5:
        line3 += r" /     "
    elif errors >= 6:
        line3 += r" / \ "
    print(f"X{line3}")
    print("X\n===========")
    if errors == 6:
        print("Hanged!")
        print(f"The secret word was: {word}")
        break