Exercise 07-11:
Modify Program 7.2 to use lists of strings to draw the hangman doll. You can use a list for each row and organize them into a list of lists. Instead of controlling when to print each part, draw on those lists, replacing the element to be drawn.
Example:
>>> line = list(“X------“)
>>> line
[‘X’, ‘-‘, ‘-‘, ‘-‘, ‘-‘, ‘-‘, ‘-‘]
>>> line[6] = “|“
>>> line
[‘X’, ‘-‘, ‘-‘, ‘-‘, ‘-‘, ‘-‘, ‘|‘]
>>> “”.join(line)
‘X-----|‘
Answer:
##############################################################################
# Python From Scratch
# Author: Nilo Ney Coutinho Menezes
# Editora Novatec (c) 2010-2025 - LogiKraft 2025
# Site: https://pythonfromscratch.com
# ISBN: 978-85-7522-949-1 (Paperback), 978-85-7522-950-7 (hardcover), 978-85-7522-951-4 (ebook)
#
# File: chapter 07/exercise-07-11.py.py
##############################################################################
words = [
"house",
"ball",
"hose",
"grape",
"okra",
"computer",
"snake",
"lentil",
"rice",
]
index = int(input("Enter a number:"))
word = words[(index * 776) % len(words)]
for x in range(100):
print()
typed = []
hits = []
errors = 0
lines_txt = """
X==:==
X :
X
X
X
X
=======
"""
lines = []
for line in lines_txt.splitlines():
# Padding spaces to each line
# in case your text editor removed the
# spaces at the end of each line
lines.append(list(line.ljust(8, " ")))
while True:
password = ""
for letter in word:
password += letter if letter in hits else "."
print(password)
if password == word:
print("You got it right!")
break
attempt = input("\nEnter a letter:").lower().strip()
if attempt in typed:
print("You already tried this letter!")
continue
else:
typed += attempt
if attempt in word:
hits += attempt
else:
errors += 1
print("You missed!")
if errors == 1:
lines[3][3] = "O"
elif errors == 2:
lines[4][3] = "|"
elif errors == 3:
lines[4][2] = "\\"
elif errors == 4:
lines[4][4] = "/"
elif errors == 5:
lines[5][2] = "/"
elif errors == 6:
lines[5][4] = "\\"
for line in lines:
print("".join(line))
if errors == 6:
print("Hanged!")
print(f"The secret word was: {word}")
break